
σ=A+Br
∫dm=∫(A+Br)2πrdr
I=∫dmr2
∫0a(A+Br)2πr3dr
=2π(A4a4+B5a5)
=2πa4(4A+5aB)
Mass per unit area of a circular disc of radius a depends on the distance r from its centre as σ(r)=A+Br . The moment of inertia of the disc about the axis, perpendicular to the plane and passing through its centre is:
Held on 7 Jan 2020 · Verified 6 Jul 2026.
2πa4(4A+5aB)
2πa4(4aA+5B)
πa4(4A+5aB)
2πa4(4A+5B)
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