P=tE
=2352×30×24×60×606.023×1026×200×1.6×10−19=60MW
In a reactor, 2kg of U23592 fuel is fully used up in 30 days. The energy released fission is 200MeV. Given that the Avogadro number, N=6.023×1026 per kilo mole and 1eV=1.6×10−19J. The power output of the reactor is close to:
Held on 2 Sept 2020 · Verified 6 Jul 2026.
35MW
60MW
125MW
54MW
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