From angular momentum conservation
Iω+0=IωC+3IωC
ωc=4ω
Loss of kinetic energy =21Iω2−21(I+3I)(4ω)2
=21Iω2−21I4ω2
=83Iω2
Fractional loss =43
JEE Main 2020 — Physics Mechanics
A wheel is rotating freely with an angular speed ω on a shaft. The moment of inertia of the wheel is I and the moment of inertia of the shaft is negligible. Another wheel of moment of inertia 3I initially at rest is suddenly coupled to the same shaft. The resultant fractional loss in the kinetic energy of the system is:
Held on 5 Sept 2020 · Verified 6 Jul 2026.
65
41
0
43
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