Fne =ma
−mg−mkv2=mvdsdv
vdsdv=−g−kv2
−∫v00g+kv2vdv=∫0hds=hmax
hmax=2K1in(gg+kv02)
A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a resistive force mkv2 where v is it speed. The maximum height attained by the ball is :
Held on 4 Sept 2020 · Verified 6 Jul 2026.
2k1tan−1gku2
k1ln(1+2gku2)
k1tan−12gku2
2k1ln(1+gku2)
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