pi=pf
mu+mucosθ=2mv
⇒v=2u(1+cos600)=43u
So horizontal range after collision =vt
=vg2Hmax
=43u2g22u2sin2(600)
=43u2g43=8g33u2
JEE Main 2020 — Physics Mechanics
A particle of mass m is projected with a speed u from the ground at an angle θ=3π w.r.t. horizontal (x-axis). When it has reached its maximum height, it collides completely inelastically with another particle of the same mass and velocity ui^. The horizontal distance covered by the combined mass before reaching the ground is:
Held on 9 Jan 2020 · Verified 6 Jul 2026.
833gu2
432gu2
85gu2
22gu2
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