Given, M=200MeVc−2 and m=1GeVc−2, now use the concept of conservation of linear momentum, Mv0=mv⇒v=mMv0...(1).
Now use the conservation of energy,
21M(v0)2=21m(v)2+ΔE..(2), here ΔE=13.6eV, for the hydrogen atom in the ground state, now from equation, (1)&(2), 21M(v0)2=41(3ΔE×810)eV=4N,
⇒4N=451eV⇒N=51.