Here Power is constant,
Hence, P=Fv=mav=av=constant.
av=kvdxdv×v=k∫0vv2dv=k∫0xdx∴v=(3k)1/3×(x)1/3⇒v=A(x)1/3whereA=(3k)1/3=constant....(1)
Also, v=dtdx∴dtdx=A(x)1/3⇒∫0d(x)1/3dx=A∫0tdt
Simplifying further we get,\Rightarrow d=At3/2 ...2
From equations (1)&(2) its clear that the graph won't be straight line so first & third options cant be correct.
Now, from equation (1) its clear that when x is increased then the slope dtds should also increase which is possible in second option. Hence option 2 is correct.



