
2g[t−21]2×21=81 ... (1)
21gt2=100 …. (2)
devide equation (1)&(2)
t−21t=910
t=5s
put t in equation (2)
g=8s2m
A ball is dropped from the top of a 100m high tower on a planet. In the last 21s before hitting the ground, it covers a distance of 19m. Acceleration due to gravity (in ms−2 ) near the surface on that planet is______
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