
From conservation of linear momentum,
Along x-axis:
10Mcos300+5(2Mcos450)=Mv1cos300+2Mv2cos450
10M23+10M21=M23v1+2Mv221
23v1+2v2=5(3+2) … (1)
Along y-axis:
−10M21+10M21=Mv121−2Mv221
2v1−2v2=5(2−1) … (2)
From equations (1) and (2)
v1(23+21)=5(3+2)+5(2−1)
v1=13.02m/s
v2=253+52−13.02×23
=19.72ms−1