JEE Main 2019 — Physics Mechanics
The trajectory of a projectile near the surface of the earth is given as y=2x−9x2. If it were launched at an angle θ0 with speed v0 then (g=10ms−2):
Held on 12 Apr 2019 · Verified 6 Jul 2026.
θ0=cos−1(51) and v0=35ms−1
θ0=cos−1(52) and v0=53ms−1
θ0=sin−1(51) and v0=35ms−1
θ0=sin−1(52) and v0=53ms−1
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