Torque about the origin =τ=r×F =rFsinθ⇒2.5=1×5sinθ sinθ=0.5=21 ⇒θ=6π
The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians):
Held on 11 Jan 2019 · Verified 6 Jul 2026.
6π
3π
8π
4π
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