g=T24π2l
gΔg=lΔl+T2ΔT
=550.1+2×(301)
=0.06848
Percentage error ≈6.8
In a simple pendulum experiment for determination of acceleration due to gravity (g), time taken for 20 oscillations is measures by using a watch of…
JEE Main 2019 — Physics Mechanics
In a simple pendulum experiment for determination of acceleration due to gravity (g), time taken for 20 oscillations is measures by using a watch of 1 second least count. The mean value of time taken comes out to be 30s. The length of the pendulum is measured by using a meter scale of least count 1mm and the value obtained is 55.0cm. The percentage error in the determination of g is close to
Held on 8 Apr 2019 · Verified 1 Jul 2026.
Options
- A
0.2
- B
6.8
- C
3.5
- D
0.7
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