Let mass of the larger triangle =M Side of larger triangle =ℓ Moment of inertia of larger triangle =ma2 Mass of smaller triangle =4M Length of smaller triangle =2ℓ Moment of inertia of removed triangle =4M(2a)2 ∴Ioriginal Iremoved =M4M⋅(a)2(2a)2 Iremoved =16I0 So,I=I0−16I0=1615I0
