
From momentum conservation,
mv+0=−mv1+Mv2...(1)
Using kinetic energy conservation,
21mv2=21mv12+21Mv22⇒21mv2=0.36×21mv2+21Mv22⇒0.64mv2=Mv22⇒v2=0.8vMm
As it retain 36,⇒0.36×(21mv2)=21mv12⇒0.36v2=v12 Hence, v1=0.6v
From (1), mv=−m(0.6v)+M(0.8vMm)
⇒1=−0.6+0.8mM
On solving, we get M=4m