From conservation of mechanical energy,
For solid sphere: 21msphV2+21Isphω2=msphghsph
2V2+5V2=ghsph
107V2=ghsph …(i)
For cylinder: 21mcylV2+21Icylω2=mcylghcyl
2V2+4V2=ghcyl
43V2=ghcyl …(ii)
From (i) and (ii) hcylhsph=1514
JEE Main 2019 — Physics Mechanics
A solid sphere and solid cylinder of identical radii approach an incline with the same linear velocity (see figure). Both roll without slipping all throughout. The two climb maximum heights hsph and hcyl on the inline. The ratio hcylhsph is given by:

Held on 8 Apr 2019 · Verified 6 Jul 2026.
52
54
1514
1
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