
From free body diagram of bead,
Ncos30∘=mg .... (1)
Nsin30∘=m2rω2 ..... (2)
By dividing equation (2) by equation (1)
tan30∘=2grω2
ω2=r32g
JEE Main 2019 — Physics Mechanics
A smooth wire of length 2πr is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed ω about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of ω2 is equal to:

Held on 12 Apr 2019 · Verified 6 Jul 2026.
2g/r
2r3g
2g/(r3)
(g3)/r
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