Work done by the force,F.s=(3i^+12j^)⋅(4i^)=12J
By work energy theorem, Wtotal=ΔK
12J=Kf−Ki12+Ki=Kf
∴Kf=12+3=15J
A particle which is experiencing a force, given by F=3i^−12j^, undergoes a displacement of d=4i^. If the particle had a kinetic energy of 3J at the beginning of the displacement, what is its kinetic energy at the end of the displacement?
Held on 10 Jan 2019 · Verified 6 Jul 2026.
9J.
15J.
12J.
10J.
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