
As 2m splits into equal parts, v1=v2 and θ=450
From conservation of linear momentum,
m(2v)+2m(v)=2[mv1cos45o]
⇒v1=v2=22v
A particle of mass m is moving with speed 2v and collides with a mass 2m moving with speed v in the same direction. After the collision, the first mass is stopped completely while the second one splits into two particles each of mass m, which move at an angle 45o with respect to the original direction. The speed of each of the moving particle will be
Held on 9 Apr 2019 · Verified 6 Jul 2026.
2v
2v
22v
(22)v
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