When cylinder is rotated, water will rise at the edge and will dip at the centre. The difference in pressure at A and O is PA−P0=ρgh. Due to height difference.
pressure difference P1−P0=ρ⋅acmR Due to rotation.
=ρ⋅(ω2.2R)R

∴ρgh=ρ2ω2R2⇒h=2gω2⋅R2=(2π×2)2×2×10(0.05)2
=0.02m
=2cm