Here, the position of the object is x=3t2+5, therefore the velocity of the object will be,
v=dtdx=dtd(3t2+5)
v=6t+0
From the work-energy theorem, all the work done by the force acting on it will be equal to the change in its kinetic energy, i.e.,
W=KE(t=5s)−KE(t=0s)
W=21×2×(6×5)2−21×2×(6×0)2
W=900J.