In first case, when 30 of the cube inside water,
ρwVing=ρcVg
VVin=ρwρc=0.3
Additional weight we can put w is,
Vρwg=ρcVg+w
w=V(ρw−ρc)g
=(0.5)3×0.7×103×g
=87.5gN
Addition of mass that we can put =87.5kg
JEE Main 2019 — Physics Mechanics
A cubical block of side 0.5m floats on water with 30 of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water?
[Take, density of water =103kg/m3 ]
Held on 10 Apr 2019 · Verified 6 Jul 2026.
87.5kg
65.4kg
30.1kg
46.3kg
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