
From conservation of linear momentum
mU=m4U+MV . . . (i)
For elastic collision: e=1=uV−4U
V=45U . . . (ii)
From equation (i) & (ii),
mU=m4U+M(45U)
m=4m+45M⇒M=53m=1.2kg
JEE Main 2019 — Physics Mechanics
A body of mass 2kg makes an elastic collision with a second body at rest and continues to move in the original direction but with one fourth of its original speed. What is the mass of the second body?
Held on 9 Apr 2019 · Verified 6 Jul 2026.
1.8kg
1.2kg
1.0kg
1.5kg
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