Velocity of 1 kg block just before it collides with 3 kg block =2gh=2000 m/s Using principle of conservation of linear momentum just before and just after collision, we get 1×2000=4v⇒v=42000 m/s Initial compression of spring 1.25×106x0=30⇒x0≈0 using work energy theorem, Wg+Wsp=ΔKE ⇒40×x+21×1.25×106(02−x2) =0−21×4×v2 solving x≈4 cm 
A body of mass 1 ~kg falls freely from a height of 100 ~m, on a platform of mass 3 ~kg which is mounted on a spring having spring constant k=1.25 ×…
JEE Main 2019 — Physics Mechanics
A body of mass 1 kg falls freely from a height of 100 m, on a platform of mass 3 kg which is mounted on a spring having spring constant k=1.25×106 N/m. The bodysticks to the platform and the spring's maximum compression is found to be x. Given that g=10 ms−2, the value of x will be close to :
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
40 cm
- B
4 cm
- C
80 cm
- D
8 cm
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