
Horizontal component of velocity vx=10cos60∘=5 m/s vertical component of velocity vy=10cos30∘=53 m/s After t=1sec Horizontal component of velocity vx=5 m/s Vertical component of velocity vy=∣(53−10)∣m/s=10−53 Centripetal, acceleration an=Rv2 ⇒R=anvx2+vy2=10cosθ25+100+75−1003 From figure (using (i)) tanθ=510−53=2−3⇒θ=15∘ R=10cos15100(2−3)=2.8 m