Centripetal force is given as F(r)=rmv2.
Given in the problem, rmV2=r16+r3...(i)
Kinetic energy is stated as KE0=21mv2.
KE0=21[16+r4] (From equation(i))
The ratio of kinetic energies of first and second particle is K2K1=216+256216+1=27217
K2K1≃6×10−2.