T=5g⇒μ(10+m)≥5g⇒10+m≥0.155
⇒m≥23.33kg⇒m=27.3kg.
JEE Main 2018 — Physics Mechanics
Two masses m1=5kg and m2=10kg, connected by an inextensible string over a frictionless pulley, are moving as shown in the figure. The coefficient of friction of horizontal surface is 0.15. The minimum weight m that should be put on top of m2 to stop the motion is:

Held on 8 Apr 2018 · Verified 6 Jul 2026.
10.3kg
18.3kg
27.3kg
43.3kg
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