As we know, Gravitational force of attraction, F=R2GMm F1=r12GMem and F2=r22GMeMs ΔF1=r132GMemΔr1 and ΔF2=r23GMeMsΔr2 Using Δr1=Δr2=2Rearth ;m=8×1022 kg; Ms=2×1030 kg r1=0.4×106 km2 and r2=150×106 km ΔF2ΔF1=(2×10308×1022)(0.4×106150×106)3×1≅2
Take the mean distance of the moon and the sun from the earth to be 0.4 × 10^6 ~km and 150 × 10^6 ~km respectively. Their masses are 8 × 10^22 ~kg…
JEE Main 2018 — Physics Mechanics
Take the mean distance of the moon and the sun from the earth to be 0.4×106 km and 150×106 km respectively. Their masses are 8×1022 kg and 2× 1030 kg respectively. The radius of the earth is 6400 km. Let ΔF1 be the difference in the forces exerted by the moon at the nearest and farthest points on the earth and ΔF2 be the difference in the force exerted by the sun at the nearest and farthest points on the earth. Then, the number closest to ΔF2ΔF1 is:
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
- A
2
- B
6
- C
10−2
- D
0.6
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