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Take the mean distance of the moon and the sun from the earth to be 0.4 × 10^6 ~km and 150 × 10^6 ~km respectively. Their masses are 8 × 10^22 ~kg…

JEE Main 2018 — Physics Mechanics

2018mcqmedium

Take the mean distance of the moon and the sun from the earth to be 0.4×106 km0.4 \times 10^6 \mathrm{~km}0.4×106 km and 150×106 km150 \times 10^6 \mathrm{~km}150×106 km respectively. Their masses are 8×1022 kg8 \times 10^{22} \mathrm{~kg}8×1022 kg and 2×2 \times2× 1030 kg10^{30} \mathrm{~kg}1030 kg respectively. The radius of the earth is 6400 km6400 \mathrm{~km}6400 km. Let ΔF1\Delta F_1ΔF1​ be the difference in the forces exerted by the moon at the nearest and farthest points on the earth and ΔF2\Delta \mathrm{F}_2ΔF2​ be the difference in the force exerted by the sun at the nearest and farthest points on the earth. Then, the number closest to ΔF1ΔF2\frac{\Delta F_1}{\Delta F_2}ΔF2​ΔF1​​ is:

Official previous-year question

Held on 15 Apr 2018 · Verified 6 Jul 2026.

Options

  1. A

    222

  2. B

    666

  3. C

    10−210^{-2}10−2

  4. D

    0.60.60.6

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