
KE2=23mv02. Conservation of momentum, v1+v2=v0. Conservation of energy, 21mv12+21mv22=21×23mv02
⇒v12+v22=23v02⇒v12+v22+2v1v2=v02⇒23v02+2v1v2=v02
⇒2v1v2=−21v02⇒(v1−v2)2=23v02+21v02=2v02
⇒v1−v2=2v0.
JEE Main 2018 — Physics Mechanics
In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50 greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after the collision, is
Held on 8 Apr 2018 · Verified 6 Jul 2026.
2v0
4v0
2v0
2v0
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