A thin uniform tube is bent into a circle of radius r in the virtical plane. Equal volumes of two immiscible liquids, whose densities are ρ1 and ρ2(ρ1>ρ2) fill half the circle. The angle θ between the radius vector passing through the common interface and the vertical is
Held on 15 Apr 2018 · Verified 6 Jul 2026.
θ=tan−1[2π(ρ1+ρ2ρ1−ρ2)]
θ=tan−12π(ρ1−ρ2ρ1+ρ2)
θ=tan−1π(ρ2ρ1)
θ=tan−12π(ρ1ρ2)
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