Equation of motion when the mass slides down Mgsinθ−f=Ma⇒10−f=6(M=2 kg,a=3 m/s2,θ=30∘ given )∴f=4 N { Equation of motion when the block is } pushed up Let the external force required to take the block up the plane with same acceleration be F F−Mgsinθ−f=Ma⇒F−10−4=6F=20 N 
A body of mass 2 ~kg slides down with an acceleration of 3 ~m / s^2 on a rough inclined plane having a slope of 30°. The external force required to…
JEE Main 2018 — Physics Mechanics
A body of mass 2 kg slides down with an acceleration of 3 m/s2 on a rough inclined plane having a slope of 30∘. The external force required to take the same body up the plane with the same acceleration will be: (g=10 m/s2)
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
- A
4 N
- B
14 N
- C
6 N
- D
20 N
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Mechanics in other years
More JEE Main Mechanics questions
If $\epsilon, E$ and $t$ represent the free space permittivity, electric field and time respectively, then the unit of $\frac{\epsilon E}{t}$ will be :
When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises upto certain height $h$. If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by $1 \%$ each, then the height of the liquid in the tube will change by $\%$.
The velocity of a particle is given as $\vec{v} = -x\hat{i} + 2y\hat{j} - z\hat{k}$ m/s. The magnitude of acceleration at point $(1, 2, 4)$ is _______ m/s$^2$.
Suppose there is a uniform circular disc of mass $M \mathrm{~kg}$ and radius $r \mathrm{~m}$ shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis $A$ of the disc is given by $\frac{x}{256} M r^{2}$. The value of $x$ is $\_\_\_\_$. 
A soap bubble of surface tension $0.04 \mathrm{~N} / \mathrm{m}$ is blown to a diameter of 7 cm. If $(15000-x) \mu \mathrm{J}$ of work is done in blowing it further to make its diameter 14 cm, then the value of $x$ is $\_\_\_\_$. ($\pi=22 / 7$)
Other Physics topics for JEE Main
Keep practicing Mechanics
Work through every JEE Main Mechanics PYQ, year by year.