Ei=−2RGMm,
Ef=−2(2R)GMm/2−2(23R)GMm/2=−2RGMm−6RGMm=−6R4GMm=−3R2GMm
Ef−Ei=2RGMm(−32+21)=−6RGMm.
JEE Main 2018 — Physics Mechanics
A body of mass m is moving in a circular orbit of radius R about a planet of mass M. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius 2R . And the other mass, in a circular orbit of radius 23R. The difference between the final and the initial total energies is
Held on 15 Apr 2018 · Verified 6 Jul 2026.
+6RGm
−2RGm
−6RGm
2RGm
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