Let acceleration be a.
Given that a=−C
We know that, a=dxvdv=−C
vdv=−Cdx
Integrating the above equation,
2v2=−Cx+k.
Thus, the velocity-distance graph is

The distance cover by the object is x=−2Cv2+Ck.
Thus, with the increase in distance, velocity decreases.
Now, a=−C=dtdv
⇒dv=−Cdt⇒v=−Ct+u,(straight line)



