mg−T=ma
RT=Iα
RT=2MR2.Ra
T=2Ma
mg−2Ma=ma
mg=a(2M+m)
mg=a(2M+2m)
a=M+2m2mg
JEE Main 2017 — Physics Mechanics
A uniform disc of radius R and mass M is free to rotate only about its axis. A string is wrapped over its rim and a body of mass m is tied to the free end of the string as shown in the figure. The body is released from rest. Then the acceleration of the body is:

Held on 8 Apr 2017 · Verified 6 Jul 2026.
2m+M2Mg
2M+m2Mg
2M+m2mg
2m+M2mg
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