P=(wsinθ+20w)10
P=(10w+20w)10=23w

2P=43w=(10w−20w)v
43=20v
15m/s=v
A car of weight W is on an inclined road that rises by 100 m over a distance of 1km and applies a constant frictional force 20W on the car. While moving uphill on the road at a speed of 10ms−1 , the car needs power P. If it needs power 2P while moving downhill at speed υ then value of υ is:
Held on 9 Apr 2016 · Verified 6 Jul 2026.
20ms−1
5ms−1
15ms−1
10ms−1
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