Viscous force =Fv=−ηA⋅dhdv
=10−3×A×3600×518×1000,[η=10−2poiseη=10−3decapoise(mks)]
∴AFv=5×360018=200×51
⇒AFv=10−3Nm−2
The velocity of water in a river is 18 km h^-1 near the surface. If the river is 5m deep, find the shearing stress between the horizontal layers of…
JEE Main 2014 — Physics Mechanics
2014mcqeasy
The velocity of water in a river is 18kmh−1 near the surface. If the river is 5m deep, find the shearing stress between the horizontal layers of water. The coefficient of viscosity of water=10−2poise.
Official previous-year question
Held on 19 Apr 2014 · Verified 6 Jul 2026.
Options
- A
10−4Nm−2
- B
10−3Nm−2
- C
10−2Nm−2
- D
10−1Nm−2
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