T=2πgL
⇒g=T24π2L
LT2=g4π2=tanθ=slope of graph
⇒g=tanθ4π2
∵tanθ=2−0.58−2=1.56=4
⇒g=44π2=(3.14)2=π2=(3.14)2=9.87ms−2

In an experiment to determine the gravitational acceleration g of a place with the help of a simple pendulum, the measured time period squared is plotted against the string length of the pendulum in the figure. What is the value of g at the place?
Held on 19 Apr 2014 · Verified 6 Jul 2026.
10.0ms−2
9.87ms−2
9.91ms−2
9.81ms−2
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