
For no slipping at P
a1+αR=a→ (1)

f=Ma1=M(a−αR)→ (2)
f. R=I⋅α=2MR2⋅α→ (3)
Solve the equations (2) and (3)
f=3Ma
JEE Main 2014 — Physics Mechanics
Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with acceleration 'a' perpendicular to the axis of the cylinder. What is Ffriction at point P ? It is assumed that the cylinder does not slip.

Held on 19 Apr 2014 · Verified 6 Jul 2026.
Ma
2Ma
3Ma
Mg
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