Using isothermal process conditions

⇒P1V1=P2V2⇒P1Aℓ1=P2Aℓ2
8p0=xp⇒p=x8p0 (here p0 = 76 cm of Hg)
x8p0+ρmg(54−x)=ρmg(76)
x8+7654−x=1
x = 16 cm
An open glass tube is immersed in mercury in such a way that a length of 8cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46cm. What will be length of the air column above mercury in the tube now ?
(Atmospheric pressure = 76cm of Hg)
Held on 6 Apr 2014 · Verified 6 Jul 2026.
16cm
22cm
38cm
6cm
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