Given: Radius of air bubble, r=0.1 cm=10−3 m Surface tension of liquid, S=0.06 N/m=6×10−2 N/m Density of liquid, ρ=103 kg/m3 Excess pressure inside the bubble, ρexe =1100Nm−2 Depth of bubble below the liquid surface, h= ? As we know, ρExcess =hρg+r2s⇒1100=h×103×9.8+10−32×6×10−2⇒1100=9800h+120⇒9800h=1100−120⇒h=9800980=0.1 m
An air bubble of radius 0.1 ~cm is in a liquid having surface tension 0.06 ~N / m and density 10^3 ~kg / m^3. The pressure inside the bubble is 1100…
JEE Main 2014 — Physics Mechanics
2014mcqhard
An air bubble of radius 0.1 cm is in a liquid having surface tension 0.06 N/m and density 103 kg/m3. The pressure inside the bubble is 1100Nm−2 greater than the atmospheric pressure. At what depth is the bubble below the surface of the liquid? (g=9.8 ms−2)
Official previous-year question
Held on 11 Apr 2014 · Verified 6 Jul 2026.
Options
- A
0.1 m
- B
0.15 m
- C
0.20 m
- D
0.25 m
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