According to Bernoulli's theorem P1+21ρv12=P2+21ρv22…(i) From question, P1−P2=3×105,A2A1=5 According to equation of continuity A1v1=A2v2 or, A2A1=v1v2=5⇒v2=5v1 From equation (i) P1−P2=21ρ(v22−v12) or 3×105=21×1000(5v12−v12⇒600=6v1×4v1⇒v12=25∴v1=5 m/s