Here, rate of fall of sand on conveyer belt, dtdm=2 kg s−1 Conveyer belt speed v=3 ms−1 Force F= ? F=vdtdm=3×2=6 N
Sand is being dropped on a conveyer belt at the rate of 2 kg per second. The force necessary to keep the belt moving with a constant speed of 3 ms−1 will be
Held on 19 May 2012 · Verified 6 Jul 2026.
12 N
6 N
zero
18 N
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