
Momentum before explosion = Momentum after explosion m×200j^=2m×400j^+2mv=2m(400j^+v)⇒400j^−400j^=v∴v=0 i.e., the velocity of the other part of the mass, v=0 Let time taken to reach the earth by this part be t Applying formula, h=ut+21gt2 490=0+21×9.8×t2⇒t2=9.8980=100∴t=100=10sec