When small droplets coelesce to form a bigger drop, energy released in this process is given by, 4πR3T[r1−R1] Where, R= radius of big drop r= radius of small drop T= surface tension According to question ⇒⇒V221mv2=4πR3T[r1−R1]21[34πR3ρ]v2=4πR3T[r1−R1]=ρ6T[r1−R1]⇒V=[ρ6T(r1−R1)]21