mgh=1/2mv2 v=2gh =2×10×80=40 m/s
A spherical ball of mass 20 kg is stationary at the top of a hill of height 100 m. It rolls down a smooth surface to the ground, then climbs up another hill of height 30 m and finally rolls down to a horizontal base at a height of 20 m above the ground. The velocity attained by the ball is
Held on 30 Apr 2005 · Verified 6 Jul 2026.
40 m/s
20 m/s
10 m/s
1030 m/s
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