Reaction: A2(g)+B2(g)⇌2AB(g)
ΔG°=−2.303RTlogK=−2.303×8.3×500×2.2=−21026 J/mol = −21.03 kJ/mol
ΔS°=2(222)−[146+280]=444−426=18 J K⁻¹ mol⁻¹
ΔH°=2(32)−[6+x]=(58−x) kJ/mol
Using ΔG°=ΔH°−TΔS°:
−21.03=(58−x)−(500×0.018)
−21.03=58−x−9=49−x
x=49+21.03=70.03≈70 kJ/mol