The solubility product constants of Ag_2CrO_4 and AgBr are 32x and 4y respectively at 298 K. The value of ( molarity of Ag_2CrO_4 molarity of AgBr )…
JEE Main 2026 — Chemistry Physical Chemistry
2026mcqmedium
The solubility product constants of Ag2CrO4 and AgBr are 32x and 4y respectively at 298 K. The value of (molarity of AgBrmolarity of Ag2CrO4) can be expressed as :
Official previous-year question
Held on 2 Apr 2026 · Verified 6 Jul 2026.
Options
A
y23x
B
2yx
C
yx
D
y3x
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Solution
Let the solubility of Ag2CrO4 be S1.
For Ag2CrO4⇌2Ag++CrO42−
Ksp=(2S1)2(S1)=4S13
4S13=32x⇒S13=8x⇒S1=23x
Let the solubility of AgBr be S2.
For AgBr⇌Ag++Br−
Ksp=S22
S22=4y⇒S2=2y
The ratio of their molarities is:
S2S1=2y23x=y3x
Answer: y3x
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