Let the solubility of Ag2CrO4 be S1.
For Ag2CrO4⇌2Ag++CrO42−
Ksp=(2S1)2(S1)=4S13
4S13=32x⇒S13=8x⇒S1=23x
Let the solubility of AgBr be S2.
For AgBr⇌Ag++Br−
Ksp=S22
S22=4y⇒S2=2y
The ratio of their molarities is:
S2S1=2y23x=y3x
Answer: y3x