For a first-order reaction, the rate constant k is given by:
k=t1/22.303log2
Using the standard approximation 2.303log2≈0.693:
k=6.930.693=0.1 min−1
The time required for 99% completion of the reaction is given by the integrated rate law:
t=k2.303log(a−xa)
Here, the initial concentration a=100 and the amount reacted x=99, so a−x=1.
t=0.12.303log(1100)
t=23.03×log(102)
t=23.03×2=46.06 minutes
Answer: 46.06