Molar mass of Ag2CO3 = 2×108+12+3×16=276 g mol−1
Number of moles of Ag2CO3 = 2762.76=0.01 mol
The decomposition reaction of silver carbonate on heating is:
Ag2CO3(s)→2Ag(s)+CO2(g)+21O2(g)
From the stoichiometry of the reaction, 1 mole of Ag2CO3 gives 2 moles of Ag as residue.
Number of moles of Ag formed = 2×0.01=0.02 mol
Mass of Ag residue = 0.02×108=2.16 g
Answer: 2.16 g