The energy of an atomic orbital in a multi-electron atom is determined by the (n+l) rule. Orbitals with a lower value of (n+l) have lower energy. If two orbitals have the same (n+l) value, the one with the lower n value has lower energy.
Calculating the (n+l) value for each given orbital:
A. n=3,l=2⇒n+l=5
B. n=4,l=0⇒n+l=4
C. n=6,l=1⇒n+l=7
D. n=5,l=1⇒n+l=6
E. n=2,l=1⇒n+l=3
Arranging the orbitals in increasing order of their (n+l) values, we get:
3<4<5<6<7
This corresponds to the order:
E<B<A<D<C
Answer: E<B<A<D<C