The balanced redox equation is: MnO2+4HCl→MnCl2+Cl2+2H2O.
Molar mass of MnO₂ = 55 + 32 = 87 g/mol.
Moles of MnO₂ = 878.7=0.1 mol.
From stoichiometry, 1 mol MnO₂ produces 1 mol Cl₂, so 0.1 mol produces 0.1 mol Cl₂.
Mass of Cl₂ = 0.1×71=7.1 g.
JEE Main 2026 — Chemistry Physical Chemistry
Aqueous HCl reacts with MnO2( s) to form MnCl2(aq),Cl2( g) and H2O(l). What is the weight (in g) of Cl2 liberated when 8.7 g of MnO2( s) is reacted with excess aqueous HCl solution?
(Given Molar mass in gmol−1Mn=55,Cl=35.5,O=16,H=1)
Held on 21 Jan 2026 · Verified 6 Jul 2026.
21.3
71
14.2
7.1
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